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Fun Math Equations Riddles in Pictures for Kids with answers



Solving mathematical equations is very much fun. Once you know the basics of mathematics, it becomes very interesting. However I have seen there are few kids who don't love mathematics as subject. If mathematics as subject can be taught in fun way then it will be more interesting and appealing to kids and we will have more kids interested in mathematics :)
Here in this post I am putting some of the mathematics equations in pictures. Kids will enjoy solving these picture mathematics equations. Answers to these equations along with detailed explanation of each of the equation is given at the end of this post. Do write your answers in the comment section of this post.
Mathematics Equations Riddle-Fruits
1. Fruits-Mathematics Equations Riddle

Mathematics Equations Riddle-Ice Cream
2. Ice Cream-Mathematics Equations Riddle

Mathematics Equations Riddle-Soft Toys
3. Soft Toys-Mathematics Equations Riddle

Mathematics Equations Riddle-Flowers
4. Flowers-Mathematics Equations Riddle

Mathematics Equations Riddle-Birds
5. Birds-Mathematics Equations Riddle

Mathematics Equations Riddle-Shapes
6. Shapes-Mathematics Equations Riddle

Mathematics Equations Riddle-Stars
7.  Stars-Mathematics Equations Riddle 
Mathematics Equations Riddle-Astronomy
8. Astronomy-Mathematics Equations Riddle



These Fun Brain Teasers are part of Fun Math Brain Teasers. Below are the next and previous math brain teasers in this series.

Hidden answers of these mathematical equations riddles is given below. To read the answer to select the text between the numbers for the corresponding answer.
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A1 .
Let me use the following notations for the figures
G............... Grapes
B............... Banana
W ..........  Watermelon
Given is
                    G + B + W= 45..........(1)
                    G + B =  15..............(2)
                    B   -  W = 1 ................(3)
 From equation 2 substituting the value of G+B IN EQUATION (1), We have
                    15 +W=  45
                  W= 45-15= 30
SUBSTITUTING VALUE OF W IN equation 3. we have 
                      B= 31 
                     G = -16
Therefore, G+B-W = -16+ 31 -30 = -15
             
A2.     17
Let me use the following notations for the figures
W..........WATERMELON,
H...............HEART
I.................ICE CREAM

2W+I = 38...........(1)
2W+H= 15.............(2)
2H+2I = 10...............(3)

From equation (1)         W= 38-I
substituting in (2)         38-I+H= 15,
                                    H - I=-23      .......(4) x 2
                                   2H - 2I = -46.............(5) 

solving equation 3 and 5 
H = -9,   I= 14, 

Substituting I in equation (1) W= 12
Hence W+H+I = 17

A3. 17

Let me use the following notations for the figures

O...........OWL
B........BEAR
T.........TIGER
GIVEN 
O+O+O= 30,..............(1)
O+B+B= 20................(2)
B+T = 3.....................(3)

From  (1),      O= 10
from (2),       10 +2B = 20,    B= 5
from (3),         B +T = 3,     T= 2
therefore , 
O+B+T= 17

A4.    12
Let me use the following notations for the figures
P............. PINK FLOWER
V.............VIOLET
Y.....   THIRD ONE
Given    P+P+P = 21....(1)
            P+V+V =  15...(2)
                 V-Y = 3.....(3)
from (1)...............P = 7,
from (2) ..........7+2V = 15,    V = 4
from (3)..........4-Y = 3,    Y= 1
therefore, P+Y+V= 12

A5.      10
Let me use the following notations for the figures
R.......RED BIRD
Y.......YELLOW BIRD
B........ BLUE BIRD
GIVEN:
R+R-Y=7..........,       2R-Y=7   .........(1)
Y+Y-B = 4.........        2Y-B= 4  .........(2)
B+B-Y= 1..........        2B-Y=1...........(3)

Multiplying equation (2) x 2 and adding it in equation (3), we have

B=2 , Y=3
substituting value of Y in (1)
R= 5 
therefore , R+Y+B = 10

A6.  14
Let me use the following notations for the figures
C........circle
P..........pentagon
T..........Triangle
Given
C+C+C=12.....        3C = 12.......(1)
C+P =19........         4+P = 19....(2)
T-P = 10.........           T- P = 10....(3)
From (1).... C = 4,
From (2).....P = 15
From (3)....T = 25
Therefore
 C+T-P  = 14

A7. 150
Let me use the following notations for the figures
S........star
C........circle
F.........flower
Given:
S x S x S = 27,   S= 3...............(1)
S x S+ C= 14,   3x3 +C= 14....(2)
C x C +F= 35,  ........................(3)

From (1), S=3
From (2) , C=5
From (3) F=35-25= 10

Therefore, SxFxC= 3x10x 5= 150

A8.   890
Let me use the following notations for the figures
S........ star
M........Moon
R......rocket

Given:
S+R+M = 60.....(1)
R+M = 50.........(2)
M-S  =  20........(3)
substituting value of R+M from (2) to (1)
S+50= 60, S=10
Substituting value of S in (3)
M= 30.
Substituting value of M in (2)
R=30
Therefore,
 R x R -S= 30x 30- 10= 900-10=890
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Below is the answer of 12th Math Picture puzzle published with title Math Brain Teasers for Kids with answers. We have hidden the answer to avoid someone looking inadvertently at the solution. Do select the text below to read the solution. >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> 
12. Lets mark the Hints from 1st to 5th from up to down.
Second Hint tells that 5 is not there in code
Third Hint when combined with 2nd Hint tells that 1 and 7 are part of code
Fourth Hint when combined with 1st Hint tell that 8 is part of code
1st Hint tells that 8 is at 3rd place
Now as 3rd place is taken by 8, 3rd Hint tells 1 at 2nd place and 7 at 1st place
So the code is 718
We don't require last hint to calculate the code. However it can be used for verification of our answer.
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