If one loves logical problems then there is a great possibility that one will love mathematics. In this post, I am putting some easy mathematical puzzles. These puzzles use a basic mathematical operation like addition, subtraction, multiplication and division.
These math riddles use BODMAS. So one must know BODMAS before trying to solve these math puzzles. Before posting these quick math riddles, let me give a quick introduction To BODMAS. While simplifying expressions involving brackets we must proceed in order of the letters of the word BODMAS. There are four types of brackets which have to be solved in the order given below.
1.    Bar
2.    Round bracket ()
3.    Curly bracket {}
4.    Square bracket []
Order of BODMAS operations is explained in the picture below with the Left side as the highest priority and right side as the lowest priority.

These math brain teasers can be used by kids. Teens in higher school will find these math questions very easy. Try not to use a calculator while solving these puzzles. It will be more fun to solve these math IQ question in case one try to solve it mentally without using any pen or pencil.
Q1. 45÷ (20-5x3)-3 of 3.

Q2. 12of 3 ÷6x3-5 of 3.

Q3. 33 ÷11 of (5x3-48 ÷4) + 10

Q4. [25-{5 of 4 ÷ (10- 5)}]

Q5. 40÷ [ 20-{10 – 5 of 2( 7-6 ) }÷10]

Q6. 2[6 of {8-(10x 4 -2 of 5)÷5}]

Q7. 10x100+ [600÷{100- (50-5x10)}]

Q8. 564 ÷141-( 10x50)+ 6of 5

Q9. 20 of { 6x4-4 of 3÷(9 x10- 3x 29)}

Q10. 56-5 of 30 ÷15

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A1.  0
45÷ (20-5x3)-3 Of 3. Using BODMAS
= 45 ÷( 20-15)-3of 3
=45÷(5)-9
=9-9=0

A2.  3
12of 3 ÷6x3-5 Of 3.
36÷6x3-15 ( solving of which means multiplication)
= 6x3-15( solving division)
= 18-15=3 ( multiplication and subtraction)

A3. 11.
33 ÷11 Of (5x3-48 ÷4) + 10
33 ÷11 of ( 15-48÷ 4)+10
33÷11 of ( 15- 12)+10
33÷ 11of 3+10
33÷ 33+10
1+10=11

A4.  21.
[25-{5 Of 4 ÷ (10- 5)}]
[25-{20÷(5)}]( solving round bracket and of)
= [25-{4}]( solving curly bracket)
= 21.( solving square bracket)

A5.  2
40÷ [ 20-{10 – 5 Of 2( 7-6 ) }÷10]
=40 ÷[20- {10-10(1)}÷10]
= 40 ÷[20-{10-10}÷10]
=40÷[20-0÷10]
= 40÷[20-0]
= 40 ÷20=2

A6.  24.
2[6 Of {8-(10x 4 -2 Of 5)÷5}]
2[6 of {8-(40-10)÷5}]
=2[6 of {8-30 ÷5}]
= 2 [ 6 of {8-6}]
=2 [6 of 2]
=2= 24.

A7. 1006
10x100+ [600÷{100- (50-5x10)}]
10x100+ [600÷{100- (50-50)}]
=10x100+[600÷{100-0}]
=10x100+[600÷100]
=1000+6=1006
.
A8. -466
564 ÷141-( 10x50)+ 6of 5
564÷141-(500)+30
=4-500+30= 34-500 =  -466

A9. 400
20 Of { 6x4-4 Of 3÷(9 X10- 3x 29)}
=20 of {6x4-4of 3 ÷(90-87)}
= 20 of {24-12÷3}
=20 of {24-4}
= 20 of 20= 400

A10.   46.
56-5 Of 30 ÷15
=56- 150 ÷15 (solving of)
=56- 10 (solving division)

=46