There are 5 algebraic picture riddles in this article. In each math picture puzzle, there are mathematical equations. The variables in these math equations are replaced with different objects. Your challenge in these fun maths riddles is to solve the algebraic equations to find the value of each variable. Once you can find the value of each variable then solve the last math equation.

Answers along with details explanations are provided at the end of this article. So let's have fun with maths and get started!

 1. Can you solve this Maths Equation?

 2. Can you solve the last equation?

 3. Can you solve this Maths Puzzle?

 4. Can you solve this Maths Brain Teaser?

 5. Can you solve this Maths Picture Puzzle?

These Fun Maths Equations Picture Puzzles are to test your Maths skills. Do check out the below listed Maths, Logic, and Picture Puzzles to test your Maths Knowledge, Logical Reasoning, and Visual Power.

## Answers to Fun Math Equations Riddles

A1.
Let me use the following notations for the figures
G............... Grapes
B............... Banana
W .......... Watermelon
Given is
G + B + W= 45..........(1)
G + B = 15..............(2)
B - W = 1 ................(3)
From equation 2 substituting the value of G+B IN EQUATION (1), We have
15 +W= 45
W= 45-15= 30
SUBSTITUTING VALUE OF W IN equation 3. We have
B= 31
G = -16
Therefore, G+B-W = -16+ 31 -30 = -15

A2. 17
Let me use the following notations for the figures
W..........WATERMELON,
H...............HEART
I.................ICE CREAM
2W+I = 38...........(1)
2W+H= 15.............(2)
2H+2I = 10...............(3)
From equation (1) W= 38-I
substituting in (2) 38-I+H= 15,
H - I=-23 .......(4) x 2
2H - 2I = -46.............(5)
solving equations 3 and 5
H = -9, I= 14,
Substituting I in equation (1) W= 12
Hence W+H+I = 17

A3. 17
Let me use the following notations for the figures
O...........OWL
B........BEAR
T.........TIGER
GIVEN
O+O+O= 30,..............(1)
O+B+B= 20................(2)
B+T = 3.....................(3)
From (1), O= 10
from (2), 10 +2B = 20, B= 5
from (3), B +T = 3, T= 2
therefore,
O+B+T= 17

A4. 12
Let me use the following notations for the figures
P............. PINK FLOWER
V.............VIOLET
Y... THIRD ONE
Given P+P+P = 21....(1)
P+V+V = 15...(2)
V-Y = 3.....(3)
from (1)...............P = 7,
from (2) ..........7+2V = 15, V = 4
from (3)..........4-Y = 3, Y= 1
therefore, P+Y+V= 12

A5. 10
Let me use the following notations for the figures
R.......REDBIRD
Y.......YELLOWBIRD
B........ BLUE BIRD
GIVEN:
R+R-Y=7.........., 2R-Y=7 .........(1)
Y+Y-B = 4......... 2Y-B= 4 .........(2)
B+B-Y= 1.......... 2B-Y=1...........(3)
Multiplying equation (2) x 2 and adding it to equation (3), we have
B=2, Y=3
substituting the value of Y in (1)
R= 5
therefore , R+Y+B = 10