Monday, January 8, 2018

Maths IQ Questions with Answers

Can you solve these Maths Equations?
Using Mathematics many different types of puzzle can be created. In some of these Maths Brain Teasers one has to find the missing number. In some of the Math Puzzles one has to find the next number in the series. In some of the Maths Picture Puzzles one has to solve the Mathematical equations where variables are represented by different symbols. Today's Maths IQ Questions are based on Mathematical equations.

How to Solve Maths IQ Questions

In each of these Maths Brain Teasers, some Mathematical equations are given. Using these equations you have to find the value of different variables in these equations and then solve the last equation.
Brain Question of Maths with answer
1. Can you solve this New Year Maths equation?

Brain Teaser in maths with answer
2. Can you solve this Maths Equations?

Maths Brainteaser picture puzzle with answer
3. Can you solve this Maths Picture Puzzle?
Easy Maths brain teaser with answer
4. Can you solve this shapes Maths Puzzle?

Mathematical Brain teaser for kids with answer
5. Can you solve this Maths Picture Equation?

You need good Mathematical knowledge to solve these Maths Picture Equation Puzzles. Do checkout below Mentioned Maths and Logic Puzzles to shake your brain.

List of Maths and Logical Puzzles

Answers of Maths IQ Questions 

A1.
Let us use the following symbols:
Clock...........L
Snowman.......S
Calendar.......C
L-S= 18...(1)
C- S = 6......(2)
C+ L= 28.....(3)
Subtracting eq (1) from (2)
C-L = -12......(4)
Adding eq (3) and (4)
2C= 16
C= 8, From eq (2) S=2
from (1), L=20
C+L+S= 30.

A2.
Let us use the following symbols:
S..........Star
N..........Snowman
P......... Penguin
S+N = 15...(1)
N+P=20....(2)
S-N=5....(3)
Adding equation (1) and (2)
2S = 20, S= 10
substituting value of S in (1).
N=5
Substituting value of N in (2)
P=15
Therefore S+N+P = 30

A3.
Let us use the following symbols:
C.........Cap
L.........Clock
N ........New year
Given:
CL+LN+NC=26..........(1)
CL+LN =18................(2)
C + N = 6.................(3)
Substituting value from (2) in (1).
NC= 8............(4)
From equation (3)
N= 6-C,
Substituting value of N in (4)
(6 -C)x C=8,
C² - 6C+ 8 = 0
C²-4C-2C +8=0
C(C-4)-2(C-4)=0
C=2, C=4
If C=2 , N=4 and if C=4, N=2 and
from eq (2)
CL+LN =18., 2L+4L=18, L= 3
CxLxN= 2x3x4 = 24.

A4.
14
Let me use the following notations for the figures
C........circle
P..........pentagon
T..........Triangle
Given
C+C+C=12..... 3C = 12.......(1)
C+P =19........ 4+P = 19....(2)
T-P = 10......... T- P = 10....(3)
From (1).... C = 4,
From (2).....P = 15
From (3)....T = 25
Therefore
C+T-P = 14

A5.
150
Let me use the following notations for the figures
S........star
C........circle
F.........flower
Given:
S x S x S = 27, S= 3...............(1)
S x S+ C= 14, 3x3 +C= 14....(2)
C x C +F= 35, ........................(3)
From (1), S=3
From (2) , C=5
From (3) F=35-25= 10
Therefore, SxFxC= 3x10x 5= 150


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